数学题1⼀3-x-2=1⼀x-3+4-2x⼀3x^2-27

2025-06-22 01:00:35

推荐回答（2个）

回答1：

1/(3-x) - 2 = 1/(x-3) + (4-2x)/(3x^2-27)
移项： 1/(3-x) - 2 - 1/(x-3) - (4-2x)/(3x^2-27) = 0
- 1/(x-3) - 2 - 1/(x-3) - 2 (2-x)/{3（x+3)(x-3)} = 0
2/(x-3) + 2 + 2(2-x)/{3（x+3)(x-3)} = 0
1/(x-3) + 1 + (2-x)/{3（x+3)(x-3)} = 0
{3(x+3) + 3(x+3)(x-3) + (2-x) } / {3（x+3)(x-3)} = 0
{3x+9 + 3x^2-27 + 2-x } / {3（x+3)(x-3)} = 0
{ 3x^2+2x-16 } / {3（x+3)(x-3)} = 0
(3x+8)(x-2) / {3（x+3)(x-3)} = 0
(3x+8)(x-2) = 0
x1=-8/3，x2=2

回答2：

你这题目有问题，能清楚点吗?该加括号的把括号加起来