化简:sin(α+β)cosα-1⼀2[sin(2α+β)-sinβ]

2025-06-21 19:14:33
推荐回答(1个)
回答1:

原式=(sinαcosβ+cosαsinβ)cosα-1/2[sin2αcosβ+cos2αsinβ-sinβ]
=sinαcosβcosα+cos²αsinβ-1/2[sin2αcosβ+(cos2α-1)sinβ]
=1/2sin2αcosβ+cos²αsinβ-1/2sin2αcosβ-1/2(1-2sin²α-1)sinβ
=cos²αsinβ-1/2(-2sin²α)sinβ
=cos²αsinβ+sin²αsinβ
=(cos²α+sin²α)sinβ
=sinβ