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碱式碳酸铜与稀盐酸反应的化学方程式是什么

2025-04-07 08:32:36

推荐回答（1个）

回答1：

cu2(oh)2co3+4hcl=2cucl2+3h2o+co2↑
222
146
270
54
44
146g×10%
xg
y
列了比例式后得出x=27g
氯化铜的质量分数？是反应后溶液的质量分数吧？
得：
y=4.4g
27g÷(30g+146g-4.4g)×100%=15.73%
呵呵，要是错了表怪我，呵呵，这类题我也不是很在行。。。。。。
仅供参考吧~

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